(r^2-4)+(4r+16)=r^2+16

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Solution for (r^2-4)+(4r+16)=r^2+16 equation: 


Simplifying
(r2 + -4) + (4r + 16) = r2 + 16

Reorder the terms:
(-4 + r2) + (4r + 16) = r2 + 16

Remove parenthesis around (-4 + r2)
-4 + r2 + (4r + 16) = r2 + 16

Reorder the terms:
-4 + r2 + (16 + 4r) = r2 + 16

Remove parenthesis around (16 + 4r)
-4 + r2 + 16 + 4r = r2 + 16

Reorder the terms:
-4 + 16 + 4r + r2 = r2 + 16

Combine like terms: -4 + 16 = 12
12 + 4r + r2 = r2 + 16

Reorder the terms:
12 + 4r + r2 = 16 + r2

Add '-1r2' to each side of the equation.
12 + 4r + r2 + -1r2 = 16 + r2 + -1r2

Combine like terms: r2 + -1r2 = 0
12 + 4r + 0 = 16 + r2 + -1r2
12 + 4r = 16 + r2 + -1r2

Combine like terms: r2 + -1r2 = 0
12 + 4r = 16 + 0
12 + 4r = 16

Solving
12 + 4r = 16

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4r = 16 + -12

Combine like terms: 12 + -12 = 0
0 + 4r = 16 + -12
4r = 16 + -12

Combine like terms: 16 + -12 = 4
4r = 4

Divide each side by '4'.
r = 1

Simplifying
r = 1

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